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lana [24]
3 years ago
9

Assume you invest $3,000 in an account that pays 7% compounded monthly. How much money will be in the account after 6 years?

Mathematics
1 answer:
omeli [17]3 years ago
6 0
Use A = P(1+r/n)^(nt).

Here, A = $3000(1+0.07/12)^(12*6).  Can you evaluate this?
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A worker is handling the four of a rectangle room that is 12 feet by 15 feet.The tiles are square with side lengths 1 1/3 feet.
Anon25 [30]

Answer:

Step-by-step explanation:

The measure of the floor of the rectangular room that is 12 feet by 15 feet. The formula for determining the area of a rectangle is expressed as

Area = length × width

Area of the rectangular room would be

12 × 15 = 180 feet²

The tiles are square with side lengths 1 1/3 feet. Converting 1 1/3 feet to improper fraction, it becomes 4/3 feet

Area if each tile is

4/3 × 4/3 = 16/9 ft²

The number of tiles needed to cover the entire floor is

180/(16/9) = 180 × 9/16

= 101.25

102 tiles would be needed because the tiles must be whole numbers.

3 0
3 years ago
A rubber ball is dropped onto a hard surface from a height of 9 feet, and it bounces up and down. At each bounce it rises to 80%
8_murik_8 [283]
There are 12 inches in a foot, so 9ft = 108in. Also, 80% = 0.8. Therefore the formula is: h(n) = 108 * 0.8^n. To find the bounce height after 10 bounces, substitute n=10 into the equation: h(n) = 108 * 0.8^10 = 11.60in (2.d.p.). Finally to find how many bounces happen before the height is less than one inch, substitute h(n) = 1, then rearrage with logarithms to solve for the power, x: 108 * 0.8^x = 1; 0.8^x = 1/108; Ln(0.8^x) = ln(1/108); xln(0.8) = ln(1\108); x = ln(1/108) / ln(0.8) = -4.682 / -0.223 = 21 bounces
4 0
3 years ago
The quadrilaterals ABBCD<br> and PQRS<br> are similar. <br> Find the length <br> of X<br> .
choli [55]
3÷3.6=5/6

4÷5/6=4.8

x=4.8
6 0
4 years ago
Find the volume of the sphere. leave your answer in terms of pi <br>r=4​
cricket20 [7]

Answer:

To find an answer in pi square the radius and multiply by pi

Step-by-step explanation:

To

find volume of a sphere = 4/3Πr³

Answer =17,164.2pi Am not sure but i hope its correct.

4 0
2 years ago
A statue that is 80 m tall stands on a 625 m2 base. An artist creates a replica using a ratio of 1:15. What is the area of the r
Sholpan [36]

Answer: 2.78m^{2}

Step-by-step explanation:

given data:

height of the statue = 80m.

base of the statue = 625m^{2}.

scale of the statue replica = 1:15.

<u><em>solution:</em></u>

= 1:15^{2} \\\\\= 1:225\\\\

= \frac{625m^{2} }{225}

= 2.78m^{2}

the area of the replica is 2.78m^{2}

4 0
3 years ago
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