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3 years ago

9

Larson's Deli orders brisket delivered every month. Last month the order was for 38 pounds and cost $304, including delivery cha

rges, which are always the same for any size order. The delivery company charges $38 for delivery. How much will this month's order for 50 pounds cost, including delivery charges?

1 answer:

scoray [572]3 years ago

5 0

Answer:

Step-by-step explanation:

38 pounds = $304

Delivery charge = $38

Last month order

38 + 38x = 304

38x = 304 - 38

38x = 266

x = 266/38

x = $7 per pounds

This months

38 + 7(50)

= 38 + 350

= $388

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Answer:

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Step-by-step explanation:

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1h/8m per hour is also 50m/8m per hour = 6.25 hours (round number)

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What is the volume of the right triangular prism shown?

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<u>Given</u>:

The sides of the base of the triangle are 8, 15 and 17.

The height of the prism is 15 units.

We need to determine the volume of the right triangular prism.

<u>Area of the base of the triangle:</u>

The area of the base of the triangle can be determined using the Heron's formula.

$S=\frac{a+b+c}{2}$

Substituting a = 8, b = 15 and c = 17. Thus, we have;

$S=\frac{8+15+17}{2}$

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Using Heron's formula, we have;

$Area = \sqrt{S(S-a)(S-b)(S-c)}$

$Area = \sqrt{20(20-8)(20-15)(20-17)}$

$Area = \sqrt{20(12)(5)(3)}$

$Area = \sqrt{3600}$

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Thus, the area of the base of the right triangular prism is 36 square units.

<u>Volume of the right triangular prism:</u>

The volume of the right triangular prism can be determined using the formula,

$V=\frac{1}{2}A_b h$

where $A_b$ is the area of the base of the prism and h is the height of the prism.

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3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago