9514 1404 393
Answer:
$2.50
Step-by-step explanation:
The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.
Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.
The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.
(8n +4p) -4(3n +2p) = (16.00) -4(6.50)
-4n -4p = -10.00 . . . . . . . . . . . simplify
n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)
The total cost for one notebook and one pen is $2.50.
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<em>Additional comment</em>
The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.
One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.
Answer:
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Step-by-step explanation:
Given
The attached graph
Required
Determine the solution
The solution here is the intersection points of the two lines. From the attachment, both lines meet


<em>Hence, the solution is: </em>
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Think about the fact that you can have two types of isosceles triangle: one of them that is a right triangle (isosceles right triangle) such as a 45-45-90 triangle and the other type can be just a regular triangle that has two sides that are congruent but it isn't a right triangle.
Thus, you would need more info about the triangles in order to conclude that the two isosceles triangles are congruent to each other.
Answer:
The corresponding segments AB and DC in the image are parallel.
Step-by-step:
It already tells us that segment QR is parallel to segment TS. So now the only segments left are segments AB and DC. Now look at segments AB and DC, do they look parallel? Yes, they do.
And that's how I got my answer. Even further, I took the test and got it right.
Your welcome. ;)