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Oksana_A [137]
3 years ago
11

In fixed deposit, a bank gives 10% interest compounded annually for senior citizens. How many complete years will it take for a

sum of money to be more than double.
Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0

Answer: 8 years

Step-by-step explanation:

You can find this out use the Rule of 72. By dividing 72 by the fixed interest rate, you can estimate the amount of time it will take for an investment to double in size:

= 72/10

= 7.2 years

= 8 complete years

Example:

Assume they invested $1,000. Interest rate is 10%.

Amount after 8 years will be:

= 1,000 * (1 + 10%)⁸

=$2,143.59

<em>Investment is now more than double. </em>

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The sum of −7 times a number and 8 times the sum of the number and 1 is the same as the number minus 7.
Novay_Z [31]

Answer:

n has no value.

There is no solution to this equation

Step-by-step explanation:

let n be the number

In pieces:

sum of the number and 1: (n + 1)

8 times the sum: 8(n + 1)

-7 times a number: -7n

sum of -7 times and...: -7n + 8(n + 1)

number minus 7: n - 7

the same as: =

All together:

-7n + 8(n + 1) = n - 7

-7n + 8(n+1)=n-7

-7n + 8n+8=n-7

0=-15

3 0
2 years ago
Need help simplifying this
diamong [38]

The simplified answer is \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}.

<u>Step-by-step explanation:</u>

$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term (\frac{3x+y}{3x+y}) and 2nd term by (\frac{z+2x}{z+2x})

= \frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= \frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}

Now, the denominators are same, you can subtract it.

= \frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

= \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

Thus the simplified solution is  \frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}

4 0
3 years ago
What is the value of <br> h(−2)<br> when <br> h(x)=3x+1
adell [148]

Replace x with -2 in the equation and solve.

3(-2) +1 = -6 + 1  = -5

5 0
2 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
maxonik [38]

Answer:

Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1

Step-by-step explanation:

This is Principle of Mathematical Induction ---PMI

Step 1: Verify that Sn is valid for n =1

Step 2:Assume that Sk is valid for n=k and prove that Sn is valid for n= k+ 1

6 0
3 years ago
What is the domain for this relation? Type the numbers in order from least to greatest,
Artist 52 [7]

Answer:

The answer is the second one.

3 0
2 years ago
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