Question

}^{?} " alt=" \sqrt{3} = {27}^{?} " align="absmiddle" class="latex-formula">

Answer 1

Let the unknown be x

$\sqrt{3} = 27^x$

$3^\frac{1}{2} = 3^{3x}$

Both the base number are 3, so we equate the exponent:

$\dfrac{1}{2} = 3x$

$x = \dfrac{1}{2} \div 3$

$x = \dfrac{1}{2} \times \dfrac{1}{3}$

$x = \dfrac{1}{6}$

Answer: 1/6