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In point for (2,7) and in Equation form x=2 y=7
The number of 10 chips stacks that Dave can make if two stacks are not considered distinct is 110.
The solution
To get the symmetric stacks, one has to subtract the symmetric stacks to know the ones that are asymmetric.
The symmetric are flipped. Given that they are double counted what we have to do is to divide through by 2.
6/2 = 3
10/2 = 5
4/2 = 2
1/2(10C6) - (5C3) + (5C3)
0.5(210-10+10)
= 110
Answer:
oh uh ok and free points LOL
Answer:
y = 16, don't know if I'm 100% right but hope this helps.
Step-by-step explanation:
since they both equal Y they may be equal to each other
Then you would subtract 2x from both sides canceling it out on one side
2x + 8 = 5x - 4
-2x -2x
This would make the equation 8 = 3x - 4
next you add the 4 from both sides
8 = 3x - 4
+4 +4
This will leave you with 12 = 3x
now you divide 3 from both sides and 12/3 = 4 makes X = 4
next you take (4) and plug it in to one of the equations
y = 2(4) + 8
y = 8 + 8
y = 16