The square of the diagonal (d1) of the end face is
.. (d1)^2 = (3 in)^2 +(5 in)^2 = (9 +25) in^2 = 34 in^2
The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
.. = (9x^2 +34) in^2
So, the longest diagonal is
.. d2 = √(9x^2 +34) in
X + 2 = 12
subtract both sides by 2
x = 10
According to the calculations made, 410 gumballs will be needed to fill the box.
Since you are trying to figure out how many gumballs you need to fill a 7.3 x 5.0 x 9.4 rectangular box for Halloween, and each gumball has a radius of 1/2 in, if the packing density for spheres is 5/8 of the volume will be filled with gumballs while the rest will be air how many gumballs will be needed, to determine this amount the following calculation must be performed:
- (Volume of box x 5/8) / volume of gumballs = Amount of gumballs
- Volume of a sphere = 4/3 x 3.14 x (radius x radius x radius)
- Volume of a gumball = 4/3 x 3.14 x (0.5 x 0.5 x 0.5) = 0.5235 inches
- ((7.3 x 5 x 9.4) x 5/8) / 0.523 = X
- (343.1 x 5/8) / 0.523 = X
- 214.4375 / 0.523 = X
- 410 = X
Therefore, 410 gumballs will be needed to fill the box.
Learn more in brainly.com/question/1578538
Answer:
56.25 feet.
Step-by-step explanation:
h(t) = 60t - 16t^2
Differentiating to find the velocity:
v(t) = 60 -32t
This equals zero when the ball reaches its maximum height, so
60-32t = 0
t = 60/32 = 1.875 seconds
So the maximum height is h(1.875)
= 60* 1.875 - 16(1.875)^2
= 56.25 feet.
