The sum of two consecutive intergers is at most 7. What is the largest possible value for the lesser interger?
1 answer:
Hello from MrBillDoesMath!
Answer: Choice "B", which is 3
Discussion:
The consecutive integers <= 7 are
1,2,3,4,5,6,7
4 is the largest number in this list that makes sense in this problem (for example, 5 + 6 > 7, 7 + 6 > 7 don't satisfy the problem)
1 + 2 = 3 <= 7
2 + 3 = 5 <= 7
3 +4 = 7 <=7 (*)
The lesser integer in the last equation (*) is 3
Thank you,
MrB
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I think it would be conditional, because B depends on A. Of A is false, then B isn’t possible, making it conditional.
C-26.5 is the answer I think hope it helped
Answer:
-7/2
Step-by-step explanation:
y2-y1 / x2-x1
-5-10 / -2-4
-15 / -6
-7 / -2
= -7/2
Answer:
31.4 is the answer......
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