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zaharov [31]
2 years ago
13

(3.5 x 10^-15) (3 x 10^-10) in scientific notation.

Mathematics
1 answer:
geniusboy [140]2 years ago
8 0
What the picture says equals:
(3.5 x 10^-5) × (3 × 10^-10) = 1.05 × 10^-14

what you typed equals:
(3.5 x 10^-15) × (3 × 10^-10) = 1.05 × 10^-24

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Plz answer ASAP tysm !
Alex777 [14]

Answer:

I already did

Step-by-step explanation:

6 0
3 years ago
Which sequence of transformations will verify that EFGH and quadrilateral EFGH and quadrilateral E'F'G'H are congruent?
levacccp [35]

D) EFGH moved onto E'F'G'H after rotating 180 counterclockwise around the origin and the reflecting across the y-axis.

<h3>How to carry out transformations?</h3>

From online resources gotten about this question, for quadrilateral EFGH and quadrilateral E'F'G'H to be congruent, what we must do first is to rotate 180° counterclockwise around the origin and then move EFGH onto E'F'G'H'.

The last step to get this proof of congruency is to reflect across the y-axis.

Read more about transformations at; brainly.com/question/4289712

#SPJ1

5 0
2 years ago
A local charity is selling seats to a baseball game. Seats cost $20 each, and snacks cost an additional $5 each.
vlada-n [284]

Answer:

let seat as x,

and snack as y.

so the linear equation is 20x+5y=400.

7 0
2 years ago
Please can some explain how to identify angles that on the same segment? ​
sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1  a° = a°  they are the same

Picture 2  p= 52°  q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4  Let the obtuse angle MOQ = 2x.  

Using the circle theorem, the angle at the centre is twice   the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

The opposite angles in a cyclic quadrilateral add up to 180°.

This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

a = 180 - 60 = 120°

8 0
3 years ago
Please answer this question! 20 points and brainliest!
azamat

Step-by-step explanation:

You have to substitute... 0, 5, & 10, & 3

y = 2x + 3

y = 2(0) + 3

y = 0 + 3

y = 3

(0,3)

y = 2x + 3

y = 2(5) + 3

y = 10 + 3

y = 13

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y = 2x + 3

y = 2(10) + 3

y = 20 + 3

y = 23

(10,23)

y = 2x + 3

y = 2(3) + 3

y = 6 + 3

y = 9

(3,9)





5 0
2 years ago
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