Question

NEED THIS NOW PLZZ!!!!

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

According to the image we have that the line goes through the following points:

$(x_ {1}, y_ {1}) :( 0, -3)\\(x_ {2}, y_ {2}) :( 6,1)$

Then, the slope is of the form:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {1 - (- 3)} {6-0} = \frac {1 + 3} {6} = \frac {4} {6} = \frac {2} {3}$

Thus, the equation is of the form:

$y = \frac {2} {3} x + b$

We know that the cut-off point is$b = -3,$ finally the equation is:

$y = \frac {2} {3} x-3$

Answer:

$y = \frac {2} {3} x-3$