12 ribbons
p.s: im in 7th grade so you can trust me
In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
Answer:
-6/5
Step-by-step explanation:
Answer:
42mm
Step-by-step explanation:
Let the shortest side of the triangle be 5x, the middle side be 6x, and the longest side be 8x.
5x+6x+8x = 159.6
19x = 159.6
x = 159.6 ÷ 19
x = 8.4
Shortest side of triangle (5x) = 8.4 × 5
= 42