2 years ago

Evaluate the expression

Mathematics

1 answer:

andreev551 [17]2 years ago

3 0

Step-by-step explanation:

this is correct answer thank you

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Step-by-step explanation:

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2 years ago

Find the equation of the line with Slope = 6 and passing through (5,38). Write your equation in the form y =mx+b

laiz [17]

Hello.

We have:

A point that the line passes through
The slope of the line

Plug the values into the Point-Slope Formula:

$\mathrm{y-y_1=m(x-x_1)}$

$\mathrm{y-38=6(x-5)}$

$\mathrm{y-38=6x-30}$

$\mathrm{y=6x-30+38}$

$\Large\boxed{\sf{ \ y=6x+8}}$

I hope it helps.

Have a nice day.

$\boxed{imperturbability}$

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Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$

Therefore:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30$

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