P = U × I
I = P / U = 1600W / 120V = 13.4A
P = 240V × 13.4A = 3216W
If your hair blower isnt rated for 220- 230V(this is the voltage in EU) you are most likely going to burn it.
I would say D. because you round to the nearest whole number and 0.04 is way less than 0.5 which is a good rounding up number.
Complete question:
A light bulb emits light that travels uniformly in all directions. Detailed measurements show that at a distance of 56 m from the bulb, the amplitude of the electric field is 3.78 V/m. What is the average intensity of the light?
Answer:
The average intensity of the light is 0.02 W/m²
Explanation:
Given;
Amplitude of the electric field, E₀ = 3.78 V/m
The average intensity of the light is calculated as follows;

where;
is the average intensity of the light
c is speed of light = 3 x 10⁸ m/s

Therefore, the average intensity of the light is 0.02 W/m²
D.
Due to the greater distance from the pivot, less force is required to crack the nut as
Moment = Force x distance.