We can use the equation vf (the final velocity) =vi (the initial velocity) +at (aceleration times time)
We know the final velocity 100m/s, the initial velocity 0, and the acceleration (gravity) 9.8m/s^2. So, 100=0+9.8t. t=100/9.8
Answer:
250 m
Explanation:
The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

where
s is the distance covered
u is the initial velocity
t is the time
a is the acceleration
Assuming the car starts from rest,
u = 0
Also we know that
a = 5 m/s^2 (acceleration of the car)
t = 10 s
Substituting, we find the distance covered:

Answer:
1. The field inside the shell is 0; TRUE
2. The field for r>R will be the same as a field for the point charge Q, at the origin: TRUE
3. only positive charges can be on the outside surface: FALSE (Negative can too!!!)
4. The field on the outside is perpendicular to the surface: TRUE
Explanation:
It is false they focus on far more important things also.
<span> The box is exerting a force of its weight. So we'll use W=mg (Note: you can use the notation F=ma, doesn't matter since weight IS a force.) We can call g negative since it's directed down towards the earth.
</span>
<span>W = 5kg(-9.8 m/(s^2)) = -49 N
</span>
<span>Thus, the box exerts a force of 49N downwards. </span>