It will lead to rain. I know this because as the clouds move over water sources like oceans, lakes, and rivers, the water evaporates and rises. The water then liquefies into little water droplets. As the cloud moves over more water the droplets get scrunched up and get bigger over time and soon they get heavy and gravity pulls the droplets down to earth as rain. The End.
44.64m
Explanation:
Given parameters:
Mass of the car = 1500kg
Initial velocity = 25m/s
Frictional force = 10500N
Unknown:
Distance moved by the car after brake is applied = ?
Solution:
The frictional force is a force that opposes motion of a body.
To solve this problem, we need to find the acceleration of the car. After this, we apply the appropriate motion equation to solve the problem.
-Frictional force = m x a
the negative sign is because the frictional force is in the opposite direction
m is the mass of the car
a is the acceleration of the car
a =
=
= -7m/s²
Now using;
V² = U² + 2as
V is the final velocity
U is the initial velocity
a is the acceleration
s is the distance moved
0² = 25² + 2 x 7 x s
0 = 625 - 14s
-625 = -14s
s = 44.64m
learn more:
Velocity problems brainly.com/question/10932946
#learnwithBrainly
The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
Learn more about Mutual inductance here-
brainly.com/question/14014588
#SPJ4
Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration, 
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,



Frictional force is given by :


F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.