Answer:
So mass of the object will be 3.2 kg
Explanation:
We have net force on the object F = 16 N
Acceleration of the object ![a=5m/sec^2](https://tex.z-dn.net/?f=a%3D5m%2Fsec%5E2)
We have top find the mass of the object
From newton law of motion we know that force is given by
F = ma , here m is mass and a is acceleration
So ![16=5\times m](https://tex.z-dn.net/?f=16%3D5%5Ctimes%20m)
![m=3.2kg](https://tex.z-dn.net/?f=m%3D3.2kg)
So mass of the object will be 3.2 kg
Answer:
Vr = 20 [km/h]
Explanation:
In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.
Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).
![V_{r}=30-10\\V_{r}=20 [km/h]](https://tex.z-dn.net/?f=V_%7Br%7D%3D30-10%5C%5CV_%7Br%7D%3D20%20%5Bkm%2Fh%5D)
Missing question: "What is the spring's constant?"
Solution:
The object of mass m=6.89 kg exerts a force on the spring equal to its weight:
![F=mg=(6.89 kg)(9.81 m/s^2)=67.6 N](https://tex.z-dn.net/?f=F%3Dmg%3D%286.89%20kg%29%289.81%20m%2Fs%5E2%29%3D67.6%20N)
When the object is attached to the spring, the displacement of the spring with respect to its equilibrium position is
![\Delta x=43.2 cm-33.6 cm=9.6 cm=0.096 m](https://tex.z-dn.net/?f=%5CDelta%20x%3D43.2%20cm-33.6%20cm%3D9.6%20cm%3D0.096%20m)
And by using Hook's law, we can find the constant of the spring:
The magnitude of charge on a proton and electron is the same, 1.602 x 10-19 C. Protons are +, and electrons -.
It is powered by the Earth's rotation and the moon gives a little boost.