Question

Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triangle formed by this line and coordinate axes.
X=(__,__)
Y=(__,__)
The area is ________
PLZ HELP I DO NOT KNOW)=

Answer 1

the coordinates of the points of intersection of the graph of y=13−x with the axes

Given equation is y=13-x

x axis is x=0

y axis is y=0

Plug in the value of x =0 and find out y

y = 13 - x

y = 13 - 0 = 13

Plug in the value of y=0 and find out x

0 = 13 - x

x= 13

So coordinate axis

x= (13,0)

y= (0,13)

Base of the triangle is x=13

Height of the triangle is y= 13

Area of the triangle = $\frac{1}{2} * base * height$

= $\frac{1}{2} * 13 * 13$ = 84.5

Area of the triangle = 84.5