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cricket20 [7]
3 years ago
7

Please solve-y(2+4y)

Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0
To solve this, you distribute the -y to both terms, 2 and 4y.
It will look something like this: (2*-y)+(4y*-y)
When you simplify, look for any like terms that can be combined, and if none, then leave it as it is. 
Your final answer will be: -2y-4y^2
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Can you guys help please im so confused
marissa [1.9K]

Answer:

a) see below

b) 40x20 meters

Step-by-step explanation:

Write down what you know:

- The area of the enclosure is length*width, so

A = x \cdot y

- The length of the fencing is 80 meters, so

2y + x = 80

Now we have to combine these two equations above, and get rid of y in the process.

First rewrite the second as:

y = 40 - \frac12 x

Then substitute for y in the first:

A = x (40 - \frac12 x) = 40x - \frac12x^2

b) To maximize A, find the zero of the first derivative:

A'(x) = 40 - x = 0 \implies x=40

So y = (80-40)/2 = 20 meters.

8 0
2 years ago
The Stomping Elephants volleyball team plays 30 matches in a week-long tournament. On average, they win 4 out of every 6 matches
8_murik_8 [283]

Answer:

The mean for the number of matches that they win in the tournament is 20.

Step-by-step explanation:

For each match, there are only two possible outcomes. Either they win, or they do not. The probability of winning a match is independent from other matches. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The Stomping Elephants volleyball team plays 30 matches in a week-long tournament.

This means that n = 30

On average, they win 4 out of every 6 matches.

This means that p = \frac{4}{6} = \frac{2}{3}

What is the mean for the number of matches that they win in the tournament?

E(X) = np = 30\frac{2}{3} = 20

The mean for the number of matches that they win in the tournament is 20.

8 0
3 years ago
Csc2theta=csctheta/2costheta<br><br>Can you help verify the identity
Yakvenalex [24]

csc(2x) = csc(x)/(2cos(x))

1/(sin(2x)) = csc(x)/(2cos(x))

1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))

(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)/(2*cos(x)) = csc(x)/(2cos(x))

The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.

7 0
3 years ago
Main Idea: To evaluate an exponential growth or decay function, substitute a value for the exponent variable and simplify.
Helen [10]
If there is more to the answer than what I give please ask for more!

With F(x) = 3^{x} we can find F(4) by substituting 4 into the main function.

So it would look like this: F(4) = 3^{4} = 3*3*3*3 = 81

Hope this helps!
3 0
3 years ago
N is the midpoint of . Find the length of the line segment PQ if NQ = 18. answers:
Vitek1552 [10]
36 because NQ is 18 and the tic mark means that each half is equal to each other, and 18+18=36 :D
5 0
3 years ago
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