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frozen [14]
3 years ago
6

True or false there is no line of symmetry in an isosceles trapezium. ​

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0

hi <3

this would be false. an isosceles trapezium has one line of symmetry down the centre

hope this helps :)

fgiga [73]3 years ago
5 0

false

Step-by-step explanation:

an isosceles has one line of symmetry going from the to to the bottom point

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A bag contains y fruits. A box can hold 4 times as many fruits as the bag.
sashaice [31]
Y = 8

A bag contains 8 fruits.
A box can hold 4 TIMES as many fruits.
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32 fruits.
3 0
3 years ago
Jarell is grocery shopping for his BBQ cookout this weekend. He is grilling 13lb. burgers and expects about 20 people. How many
user100 [1]

Jarrell should purchase 7 lbs of ground beef.

Number of attendees = 20

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Total fraction of burger required to feed 20 persons :

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Learn more : brainly.com/question/2610134

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3 years ago
HELPPPP ASAPPP PLEASSSSEE
kolezko [41]

Let dimes = d and quarters =q

D + q = 50

D= 50-q

0.10d + 0.25Q = 7.70

Replace d with 50-q:

0.10(50-q) + 0.25q = 7.70

Simplify:

5 -0.10q + 0.25q = 7.70

5 + 0.15q = 7.70

Subtract 5 from both sides:

0.15q = 2.70

Divide both sides by 0.15:

Q = 2.70 / 0.15

Q = 18

D = 50-18 = 32

There are 32 dimes and 18 quarters

5 0
3 years ago
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Which equation does not have the same solution as the others?
ladessa [460]
X/4 = 2.....x = 8
x - 9 = 17....x = 26 <=== there is the odd ball
x + 12 = 20....x = 8
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4 0
3 years ago
25 POINTS AND BRAINLIEST PLEASE HELP ASAP
dexar [7]
M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=&#10;\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\&#10;\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
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3 years ago
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