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marusya05 [52]
3 years ago
10

What is the area of a regular hexagon with a side length of 6 yd? Enter your answer in the box. Round only your final answer to

the nearest hundredth.
___yd²
Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer: 93.53\ \text{yd}^2

Step-by-step explanation:

Given: The side-length of a regular hexagon = 6 yards

The area of regular hexagon is given by  :-

\text{Area}=\frac{3\sqrt{3}}{2}\text{(side)}^2

Substitute side = 6 yards in the above formula, we get

\text{Area}=\frac{3\sqrt{3}}{2}(6)^2\\\\\Rightarrow\text{Area}=93.5307436087\approx93.53\ \text{yd}^2

tatuchka [14]3 years ago
5 0
Your answer would be 93.53
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2 years ago
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(a) The probability that an automobile being filled with gasoline will also need an oil change is 0.35; the probability that it
cricket20 [7]

Answer:

0.714 ; 0.556 ; (A1 n A2 n A3) = 0

Step-by-step explanation:

Given that :

P(oil) = 0.35

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P(oil n filter) = 0.25

1)

P(filter | Oil) = P(oil n filter) / P(oil)

P(filter | Oil) = 0.25 / 0.35 = 0.714

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P(Oil | filter) = P(oil n filter) / P(filter)

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Number of red aces = 2

Queen or king = 4 + 4 = 8

Number on card greater than 3 and less than 8 = {4,5,6,7} = 4 card ; for 4 suits = 4 * 4 = 16

Total number of cards in deck = 52

Choosing without replacement :

Hence,

A1 = 2 / 52

A2 = 8 / 51

A3 = 16 / 50

(A1 n A2 n A3) ;this means card common to all three events.

However, (A1 n A2 n A3) = 0 because ;

1.) No red ace card is greater than 3 and less than 8.

11.) An ace card can neither be a king nor a queen

3 0
3 years ago
justin needs to make 80 illustrations for an art book. He has made 40% of that illustrations. Make a bar model to show his progr
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Step-by-step explanation:

That is my answer, luckily I did the test

6 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. a delivery of 6 large boxes and 5 small boxes has a t
Afina-wow [57]
6 large + 5 small = 127 kg ------------ (1)
2 large + 3 small = 51kg    ------------ (2)

<u>(2) x 3 :</u>
6 large + 9 small = 153 ---------------- (2a)

<u>(2a) - (1) :</u>
4 small = 26
1 small = 6.5kg   ------------ (sub into equation 1)

6 large + 5 small = 127 kg
6 large + 5(6.5) = 127
6 large + 32.5 = 127
6 large = 127 - 32.5
6 large = 94.5
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Answer: The small box weighs 6.5kg and the big box weighs 15.75 kg


5 0
3 years ago
Calculate the area of the shaded sector in the circle​
agasfer [191]

Answer:

Approximately, 6.283..

Step-by-step explanation:

First calculate the area of the whole circle

We have radius(r)=4 cm

Area of circle(a)=pir^2

=pi×(4)^2

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A cirlce has a total of 360 degrees

Therefore,we can conclude 360 degrees=50.265...

or,1 degree=50.265/360

1 degree=Approximately,0.139

Now,

Area for the shaded region = Area of 45 degree

=0.139×45=Approximately,6.283.....

Therefore,the area of the shaded region is approximately,6.283....

6 0
3 years ago
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