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marusya05 [52]
3 years ago
10

What is the area of a regular hexagon with a side length of 6 yd? Enter your answer in the box. Round only your final answer to

the nearest hundredth.
___yd²
Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer: 93.53\ \text{yd}^2

Step-by-step explanation:

Given: The side-length of a regular hexagon = 6 yards

The area of regular hexagon is given by  :-

\text{Area}=\frac{3\sqrt{3}}{2}\text{(side)}^2

Substitute side = 6 yards in the above formula, we get

\text{Area}=\frac{3\sqrt{3}}{2}(6)^2\\\\\Rightarrow\text{Area}=93.5307436087\approx93.53\ \text{yd}^2

tatuchka [14]3 years ago
5 0
Your answer would be 93.53
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Answer:

<em>outliers</em>

Step-by-step explanation:

An outlier is a data point that is significantly different from other observations. An outlier might be due to inconsistency in measurements, or due to an error introduced into the experiment. Outliers cans lie extremely high or low of other observation in statistics, and they usually create a big problem for  proper analysis.

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many credit card companies charge a compound interest of 1.8% per month on a credit card balance. Miriam owes 750 on a credit ca
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Answer:

Most credit card companies also apply a late payment penalty if you owe a balance and do not make a payment. Ignoring that fee, Miriam's balance will increase as:  

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$750.00  

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Step-by-step explanation:


6 0
3 years ago
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Which of the following has no solution?
Softa [21]

Answer:

(x + 1 s 1) n (x + 12 1)

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Step-by-step explanation:

Just simplify each the statements.

Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.

(x + 1<-1) n (x + 1< 1)

(x <-2) n (x < 0) which is true, so there is a solution.

(x + 1 s 1) n (x + 12 1)

this doesn't make sense so there is no solution.

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3 years ago
A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a
Vesnalui [34]

Answer:

2.5

Step-by-step explanation:

A triangle ABC with vertices A(0, 0), B(0, 4), and C(6, 0) is dilated to form a triangle A'B'C' with vertices A′(0, 0), B′(0, 10), and C′(15, 0). If the center of dilation is point A or A' (the origin), then

\dfrac{A'B'}{AB}=\dfrac{A'C'}{AC}.

Since

  • AB=4;
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  • A'C'=15,

then the scale factor of the dilation is

k=\dfrac{10}{4}=\dfrac{15}{6}=2.5.

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