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lbvjy [14]
3 years ago
10

Frank is trying to factor y^2+6y-27 . He has determined that one factor is (y + 9). What is the other factor? A. y – 27 B. y – 6

C. y – 9 D. y – 3
Mathematics
2 answers:
beks73 [17]3 years ago
5 0
The other factor is (y - 3).  If you multiply the two terms together, you will end up with y^2+6y-27:

(y - 3)(y + 9) \\ y^{2} +9y-3y-27 \\ y^2+6y-27
Doss [256]3 years ago
4 0
Identify b and c in the equation:

b = 6
c = -27

Two factors must add to b, and two factors must multiply to c.

We know that one of the factors is 9, so we can set up the following equations to solve for the missing factor:

9 + y = 6

Subtract 9 from both sides:

y = -3

-

9y = -27

Divide both sides by 9 to get y by itself:

y = -3

The other factor is D. (y - 3).

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Does she get more money during the other months, just as she had gotten 5 times as much as she had in a 3 month span? (From june to september.) All I could tell was her money was multiplied by 5, then you add $87.83 more into her account.

Please check my math if you want to be sure.
$76.23 * 5 = $381.15
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3 years ago
If it takes 12 minutes to cut a log into 4 pieces, how many minutes will it take to cut a log into 3 pieces?
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Answer:

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<h2><u>Answer :</u></h2>

‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ\bigstar\boxed{\large\bf{\leadsto -\dfrac{28}{9}}}

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<h2><u>Calculation</u><u> </u><u>:</u></h2>

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼ \dfrac{\dfrac{14}{9}}{\dfrac{-1}{3}-\dfrac{1}{6}}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼ \dfrac{\dfrac{14}{9}}{\dfrac{-2-1}{6}}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼ \dfrac{\dfrac{14}{9}}{\dfrac{-3}{6}}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\dfrac{14}{9}\times -2}

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‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\bf{⟼\dfrac{-28}{9}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎

⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀

8 0
3 years ago
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AlladinOne [14]

Answer:A= 1,2 B=1,2 C=-9,10

Step-by-step explanation:

For A=

To find A', reflect the triangle exactly over the y-axis. That will put your A' at (1,2)

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translate the triangle clockwise around the origin, (0,0), to put B' at (1,2)

For C= Translate point C to the left 4, and up 2, so the answer is (-9,10)

8 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
3 years ago
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