From the information you have given me, I would say Kimmy has $<span>468.98 </span>dollars in her bank account.
Does she get more money during the other months, just as she had gotten 5 times as much as she had in a 3 month span? (From june to september.) All I could tell was her money was multiplied by 5, then you add $87.83 more into her account.
Please check my math if you want to be sure.
$76.23 * 5 = $381.15
$381.15 + 87.83 = 468.98
Answer:
9 minutes
Step-by-step explanation:
<h2><u>Answer :</u></h2>
ㅤㅤㅤㅤㅤ
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
<h2><u>Calculation</u><u> </u><u>:</u></h2>





⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀
Answer:A= 1,2 B=1,2 C=-9,10
Step-by-step explanation:
For A=
To find A', reflect the triangle exactly over the y-axis. That will put your A' at (1,2)
For B=
translate the triangle clockwise around the origin, (0,0), to put B' at (1,2)
For C= Translate point C to the left 4, and up 2, so the answer is (-9,10)
Answer:
the rate of change of the water depth when the water depth is 10 ft is; 
Step-by-step explanation:
Given that:
the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.
We are meant to find the rate of change of the water depth when the water depth is 10 ft.
The diagrammatic expression below clearly interprets the question.
From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t
Then the similar triangles ΔOCD and ΔOAB is as follows:
( similar triangle property)


h = 2.5r

The volume of the water in the tank is represented by the equation:



The rate of change of the water depth is :

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec
Then,

Therefore,

the rate of change of the water at depth h = 10 ft is:




Thus, the rate of change of the water depth when the water depth is 10 ft is; 