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nevsk [136]
3 years ago
12

If you had an additional 1.65 pounds to download songs, how many more songs could you have downloaded? Write and solve an equati

on to solve the problem. Describe the step-by-step process you used to solve the problem.
I only need the graph plzz

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

6.0p+1.65p=7.65

Step-by-step explanation:

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I’m in desperate need of help
Tomtit [17]
I may not be able to help you but i do feel your pain lol
4 0
3 years ago
If (k,6k) and (3k,10k) are two points on the graph of a line and K is not equal to 0, what is the slope of the line?
Nataliya [291]

Answer:

Step-by-step explanation:

slope = y2-y1/x2-x1

Given the coordinates (k,6k) and (3k,10k)

x1 = k

y1 = 6k

x2 = 3k

y2 = 10k

Substitute

slope = 10k-6k/3k-k

slopw = 4k/2k

slope = 4/2

slope  = 2

Hence the slope of the line is 2

7 0
3 years ago
Which equation is equivalent to log Subscript 3 Baseline (x + 5) = 2?
adell [148]

Answer:

The correct option is right-bracket squared 3 squared =x+5

Step-by-step explanation:

The equation is \log _{3}(x+5)=2

Option a: \log _{3}(x+5)=3^{2}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option a is not equivalent to \log _{3}(x+5)=2

Option b: \log _{3}(x+5)=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Option c: x+5=3^{2}

This is possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option c is equivalent to \log _{3}(x+5)=2

Option b: x+5=2^{3}

This is not possible because using logarithmic rule, if \log _{a} b=c then b=a^{c}

Hence, option b is not equivalent to \log _{3}(x+5)=2

Thus, the correct option is c: x+5=3^{2}

Hence, the equation x+5=3^{2} is equivalent to \log _{3}(x+5)=2

8 0
3 years ago
Lcm of (x-2)(x+3) and 10(x+3)^2
Arte-miy333 [17]
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:

(x - 2)(x + 3)          10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²

Answer: LCM is 10(x - 2)(x + 3)²


8 0
3 years ago
Solve with a system of equations: Two angles are supplementary if the sum of their measures are 180 degrees. If one is 90 degree
julsineya [31]

Answer:

  The measures of the angles are 150° and 30°.

Step-by-step explanation:

Let x and y represent the measures of the angles, with x representing the larger angle.

  x + y = 180 . . . . . . the two angles are supplementary

  x = 90 + 2y . . . . . one is 90° more than twice the other

___

Substituting the expression given by the second equation into the first, we have ...

  (90 +2y) +y = 180

  3y = 90 . . . . . . . . . . collect terms, subtract 90

  y = 30 . . . . . . . . . . . divide by the coefficient of y

  x = 180 -y = 150

The measures of the angles are 150° and 30°.

6 0
3 years ago
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