Question

If f(x) =-x^2 +6 x-1 and g(x) =3x^2-4x-1 find ( f+g) (x)

Answer 1

$(f+g)(x)=-x^2+6x-1+3x^2-4x-1=2x^2+2x-2$

Answer 2

Answer: $(f+g)(x)=2x^2+2x-2$

Step-by-step explanation:

Given the function f(x), which is:

$f(x)=-x^2 +6x-1$

And the function g(x), which is:

$g(x) =3x^2-4x-1$

You can observe that $(f+g)(x)$ indicates that you need to add the functions, then you know that:

$(f+g) (x)=(-x^2+6 x-1)+(3x^2-4x-1)$

Finally, to simplify it you must addthe like terms. Therefore, you get that  $(f+g)(x)$ is:

$(f+g)(x)=-x^2+6 x-1+3x^2-4x-1$

$(f+g)(x)=2x^2+2x-2$