All categories

2 years ago

Someone help pls -……

Mathematics

1 answer:

uysha [10]2 years ago

8 0

Answer:

d) 35ft

e) 6 seconds

f) 250°

Step-by-step explanation:

If it makes one rotation (360°) in 36 seconds, then it turns 10° every second.

36 secs = 360°

⇒ 1 sec = 360/36 = 10°

d) After 9 seconds, it has turned:

9 x 10 = 90°

Therefore, it will be 15 + 20 = 35ft from the wall

e) 60° = 6 seconds

f) 25 seconds = 25 x 10 = 250°

You might be interested in

Damien Smart is trying to decide whether to lease or purchase a new car costing $18,000. If he leases, he’ll have to pay a $600

gizmo_the_mogwai [7]

$the\ lease:\\\\ \$450\cdot36(payments)- \$600(security)=\$16,200-\$600=\$15,600 \\\\ the\ purchase:\\\\down\ payments+payments+sales\ tax- residual\ value= \\\\=\$2,400+\$515\cdot36+\$1,080-\$6,500=\$2.400+\$18,540-\$5420=\\\\=\$15,520\\\\\$15,520$

6 0

2 years ago

Read 2 more answers

Question 3 Unsaved

bazaltina [42]

Answer:

Step-by-step explanation:

DE given is

y''+8y'+15y=0, y(0)=0, y'(0)=1

Take Laplace on the DE

We get

$s^2 Y(s) -sY(0) -y'(0)+8(sY(s)-y(0))+15Y(s) =0\\s^2 Y(s) -s(0) -1+8(sY(s)-0)+15Y(s) =0\\Y(s)(s^2+8s+15)-1=0\\Y(s) = \frac{1}{s^2+8s+15}$

Simplify to get

Y(s) = $\frac{1}{2}[ {\frac{1}{s+3} -\frac{1}{s+5} }]$

Take inverse

$y(t) = \frac{e^{-3t} -e^{-5t}}{2}$

8 0

3 years ago

Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe

Stolb23 [73]

Answer:

Step-by-step explanation:

The model $N (t)$ , the number of planets found up to time $t$ , as a Poisson process. So, the $N (t)$ has distribution of Poison distribution with parameter $(\lambda t)$

The mean for a month is, $\lambda = \frac{1}{3}$ per month

$E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8$

(Here. t = 24)

For Poisson process mean and variance are same,

$Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8$

(Poisson distribution mean and variance equal)

The standard deviation of the number of planets is,

$\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828$

For the Poisson process the intervals between events(finding a new planet) have independent exponential distribution with parameter $\lambda$ . The sum of $K$ of these independent exponential has distribution Gamma $(K, \lambda)$ .