Answer:
He should get his mitochondrial haplotype sequenced, given the genetic variation in mitochondrial sequences compared to Y chromosomes.
Explanation:
- Mitochondrial DNA haplotypes are  specific regions of mitochondrial DNA that cluster with other mitochondrial sequences to show the phylogenetic origins of maternal lineages. 
- Mitochondrial DNA haplotypes are associated with a range of phenotypes and disease.
- Mitochondrial DNA contains 37 genes, all of which are essential for normal mitochondrial function.
- Thirteen of these genes provide instructions for making enzymes involved in oxidative phosphorylation.
 
        
             
        
        
        
Sun heat highly temperature. water was can vapor atmosphere
        
                    
             
        
        
        
This process is called osmosis whereby water exits the cell through its selectively permeable membrane and into the salt solution to dilute and balance the pressure caused by the concentrated salt solution.
        
                    
             
        
        
        
Answer:
Ok, no boxes but whatever
Mammals - Endothermic Homeostasis (Warm Blooded), Hairy Body, Have babies live
Birds - Endothermic Homeostasis(Warm Blooded), Have eggs, feathers, claws
Bacteria - Single celled, use binary fission to divide
Fungi - Multi or single celled, have chitin cellular walls
Plants - Have cellulose plant walls, multicellular organism
Archae Bacteria - Same as normal, except they live in crazy enviorments, like at the bottom of the ocean or in a volcano or radiation pool
Protozoa - Single celled organism class, like ameoba 
 
        
             
        
        
        
Answer:

Explanation:
Straight wings are dominant over curved wings
Let Straight wings : H
curved wings : t
smooth eyes are dominant to sparkling eyes
 let smooth eyes = H
 spark ling eyes = t
tan body is dominant to ebony body color.
Again; Let tan body color be H
Let ebony color be t
If flies that are heterozygous for all three traits are crossed;
 we have HtHtHt × HtHtHt
Then the selected trihybrid traits for the cross will be (HHH,HHt, HtH, Htt, tHH, tHt, ttH, ttt)
We will realize that from the punnet square in the diagram below, the proportion of the offspring would you expect to be heterozygous for all three traits (i.e HtHtHt) is asterisk in the punnet square and will be 
= 