Answer:
there's no picture
Step-by-step explanation:
Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that

For parts (a) and (b), you're given everything you need to determine

.
For part (c), if

and

are mutually exclusive, then

, so

. If the given probability is

, then you can find

. But if this given probability is for the intersection, finding

is impossible.
For part (d), if

and

are independent, then

.
Answer:
A. 3, 0, -3, -6
Step-by-step explanation:
The sequence with constant first differences is an arithmetic sequence. The sequence of A has a common difference of -3, so is an arithmetic sequence.
Answer:
The median is marked at 161cm instead of 162cm.
The right part of the box (the upper quartile) is marked at 172cm, while the interquartile range is 17cm, so the upper quartile should be at 154cm + 17cm = 171cm.
The cost of 1 liter for the small and medium cans is 4.4 and 2.4.
<h3>What is Unitary method?</h3>
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
As,
Small can: A 200 ml can costs £0.88.
Medium can: A 500 ml can costs £1.32.
Large can: A 1 litre can costs £3.60.
Now, 200 ml = 0.2 l
500 ml = 0.5 l
For 0.2 l = 0.88
For 1 l= 0.88/0.2
For 1 liter = 4.4
For 0.5l medium can = 1.32
For 1 l medium can= 1.32/0.5
For 1 l medium can = 2.4
Hence, cost of 1 liter for the small can is £ 0.88 the cost of 1 liter for the medium can is £ 2.4.
Learn more about this concept here:
brainly.com/question/22469540
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