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trasher [3.6K]
3 years ago
9

For the past three months , grace used her cell phone for 43 minutes , 62 minutes, and 57 minutes

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
Nig u stoppad  loser and butt hole
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A vehicle travels a distance of 504 - 10+ 6 miles in + 2 minutes. The vehicle's speed is miles/minute.​
laiz [17]

Answer:

502

Step-by-step explanation:

504-10=494

494+6=500

500+2=502

answer 502

6 0
3 years ago
Olivia is thinking of a number.She says, "My number is odd. It is a factor of 30 and a multiple of 3"
Katarina [22]

Answer:

15

Step-by-step explanation:

Factors of 30:

1 , 2, 3, 5, 6, 10, 15, 30

Multiples of 3:

3, 6, 9, 12, 15, etc.

The first number (and only number) shared by both sets is 15, therefore 15 is your answer.

~

8 0
3 years ago
Read 2 more answers
Thomas buys a cardboard sheet that is 8 by 12 inches. Let x be the side length of each cutout. Using complete sentences, explain
jasenka [17]

Answer: V = (12in - 2*x)*(8 in - 2*x)*x

Step-by-step explanation:

So we have a rectangular cardboard sheet, and we cut four squares of side length x in each corner so we can make a box.

Remember that for a box of length L, width W and height H, the volume is:

V = L*W*H

In this case, the length initially is 12 inches, but we remove (from each end) x inches of the length, then the length of the box will be:

L = 12 in - 2*x

For the width we have a similar case:

W = 8in - 2*x

And te height of the box will be equal to x, then:

H = x

This means that the volume is:

V = (12in - 2*x)*(8 in - 2*x)*x

Here we can see the connection between the cutout and the volume of the box

7 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
3 years ago
26. A(-4, -1), B(-4, 6), C(2,6), D(2, -4)
Fudgin [204]

Answer:

I NEEEEEEEED TO SEEEE GRAPHHHHHHHHHHHH

Step-by-step explanation:

5 0
2 years ago
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