Given:
Line A:
Line B:
Line C:
Line D:
To find:
Which lines are perpendicular
Solution:
General equation of a line:
y = mx + c
where m is the slope and c is the y-intercept.
Slope of line A =
Slope of line B =
Slope of line C = 2
Slope of line D =
<em>Two lines are perpendicular if their slopes are negative reciprocal of one another.</em>
Negative reciprocal of is 2.
Therefore line B and line C are perpendicular lines.
Answer:
C. –x + 8y = 56
Step-by-step explanation:
Write in standard form.
x − 8 y = − 56
This is a linear function in the slope - intercept form:
y = m x + b and we need a standard form:
a x + b y = c
y = 1/8 x + 7 / * 8 ( we will multiply both sides of equation by 8 )
8 y = x + 56
- x + 8 y = 56 / * ( - 1 )
x - 8 y = - 56
The equation is y = 1/8x + 7
Standard form equation is Ax + By = C, where A > = 0.
First eliminate the fractions by multiplying the equation by 8
8y = x + 56
Subtract x from each side
-x + 8y = 56
SInce x coeficient can't be negative multiply the equation by negative one.
x - 8y = -56
