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3 years ago

Joe must choose a number between 67 and 113 that is a multiple of 3 , 5, 6 write all numbers that he could choose

Mathematics

1 answer:

irinina [24]3 years ago

8 0

Answer:

The only number he could choose is 90

Step-by-step explanation:

Simply put, we want to find the numbers between 67 and 113 which are multiples of 3,5 and 6.

Kindly note that, the numbers we will be choosing will be multiples of the three numbers at the same time.

Multiples of 3 here are;

72 , 75 , 78 , 81 , 84 , 87 , 90 , 93 , 96 , 99 , 102 , 105 , 108 , 111

Multiples of 6 here are

72, 78 , 84 , 90 , 96 , 102 , 108

Multiples of 5 here are

70, 75 , 80 , 85 , 90 , 95 , 100 , 105 , 110

So therefore, the only number that works here is the number 90

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If m ABC=122 and m ABD=71 then m DBC =

Marysya12 [62]

Answer:

Angle DBC = 51

Step-by-step explanation:

Angle ABC = angle ABD + angle DBC

We are given that angle ABC = 122 and angle ABD = 71

So 122 = 71 + angle DBC

* Solve for angle DBC *

Subtract 71 from both sides

122 - 71 = 71 - 71 + angle DBC

51 = angle DBC

5 0

3 years ago

Read 2 more answers

Evaluate cos0 if sin0= sqrt(5)/3 a. 9/5 b. 2/3 c. 5/9 d. 3/2

Evgesh-ka [11]

Solution given:

$\sin( \alpha ) = \frac{\sqrt{5} }{3}$

P=√5

h=3

b= $\sqrt{3 {}^{2} - \sqrt{5} {}^{2} }$

b=2

$\cos( \alpha ) = \frac{b}{h} = \frac{2}{3}$

Note

$\alpha = 0$

b:⅔

8 0

3 years ago

Marissa has 2.5 hours of swim practice per day. She practices 4 days per week. The swimming season is 14 weeks long.

AveGali [126]

Answer: 140

Step-by-step explanation: 2.5 x 4 = 10

10 x 14 = 140

you multiply the amount of hours she swims for 4 days and then multiply those hours by 14 because the swimming season is 14 weeks long.

7 0

3 years ago

n the graph below determine how many real solutions the quadratic function has, and state them, if applicable. List solutions in

IRINA_888 [86]

Answer:

There are no real solutions.

Step-by-step explanation:

There are 3 options.

2 real solutions: This happens if in the graph, each arm intersects the x-axis, this means that there are two different values of x such that the equation:

a*x^2 + b*x + c

is equal to zero.

Another way to see this, is if the determinant:

b^2 - 4*a*c

is larger than zero.

1 real solution: This happens when the vertex of the graph intersects the x-axis. This means that there is a single value of x such that:

a*x^2 + b*x + c

is equal to zero.

Another way to see this is if the determinant:

b^2 - 4*a*c

is larger equal zero.

No real solution: if in the graph we can not see any intersection of the x-axis, then we do not have real solutions (only complex ones).

Another way to see this is if the determinant:

b^2 - 4*a*c

is smaller than zero.

Now that we know this, let's look at the graph.

We can see that the vertex is below the x-axis, and the arms of the graph go downwards. So the arms will never intersect the x-axis (and neither the vertex).

So the graph does not intersect the x-axis at any point, which means that there are no real solutions for the quadratic equation.

The correct answer would be "none"

3 0

3 years ago

Which of the following rational functions is graphed below?

podryga [215]

Answer:

Step-by-step explanation:

Oblique Asymptotes

R(x) will have oblique asymptote if it can be represented in the form

1 / (Q)x

4 0

2 years ago