Answer:
a change in the state of matter
Step-by-step explanation:
After using the algebraic equation, the required value of x = 55/2.
WHAT IS ALGEBRIC EQUATION?
A mathematical statement wherein two expressions have been set equal to one another is known as an algebraic equation. A variable, coefficients, and constants make up an algebraic equation in most cases. Equations, or the equal sign, simply indicate equality. Equating each quantity with another is what equations are all about. Equations act as a scale of balance. If you've ever seen a balance scale, users know that for the scale to be deemed "balanced," an equal amount of weight must be applied to each side. The scale will tip to one side if we only add weight to one side, and the two sides will no longer be equally weighted.
(x-3)2 = 49
= x-3 = 49/2
= x = (49/2) + 3
= x = 55/2
So, the required value of x = 55/2.
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Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles
time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)
Marcus travels 78000(2)(square) +32500(2)
= 84500yards
=48 miles
time = distance/speed
time=48/45
time=1.07 (1 hour 7 mins)
a)Josephine arrives first
b)she arrives earlier by 2 mins.
we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
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