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3 years ago

I need help again...sorry and thanks

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

5 0

3.2 < 3.2041 < 3.24 < 5.112

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I need help with this math problem. Check images.

Artemon [7]

Answer:

1,2,4,6,8,9,10,13

Step-by-step explanation:

4 0

3 years ago

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Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

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2 years ago

Plz do both plz plz plz

vlada-n [284]

Answer:

3. 18 meters.

4. A= 6. 25cm^2 and P= 10 cm

5. 16 feet and 3 feet.

Step-by-step explanation:

3. base= 2 (A/h)

2 (72/8) = 18

4. A= side^2

2.5^2 = 6.25

P= 4 sides

2.5 x 4= 10

5. 16x3= 48

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3 years ago

I need help with some homework

8_murik_8 [283]

Yes they are , since they are very common in ones body

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3 years ago

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The cube has a volume of 64 cubic inches. What is the length of a side of the cube? Explain. PLEASE HURRY!

Nostrana [21]

Answer:

Step-by-step explanation:

a^3 = 64

therefore , a = 4

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3 years ago

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