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exis [7]
3 years ago
12

I need help again...sorry and thanks

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
5 0
3.2 < 3.2041 < 3.24 < 5.112
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Here are two patterns made using identical rhombuses. Without using a protractor, determine the value of a and b.
satela [25.4K]

Answer:

<em>a = </em>60°

<em>b </em>=<em> </em>120°

Step-by-step explanation:

First, you can find measure <em>a </em>by using the first shape. There are six rhombuses, and you can use the innermost <em>a </em>of each one to form a circle. A full circle is 360°, so divide 360 by six. The answer is sixty. So on the next shape, the <em>a</em> measurements add up to 120°. Subtract that from the circle: 360 - 120 = 240. And since there are two measurements for <em>b</em>, you would divide 240 by two. The answer is 120.

To check your work, use the knowledge that circles are 360° (the four interior corners of a rhombus will also add up to 360°. 2(120) + 2(60) = 360. Hope this helps! Feel free to ask any questions!

7 0
3 years ago
Read 2 more answers
Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0
4 years ago
HELPPPPPPPPPPPPPPPPPPP!!!
Zielflug [23.3K]

Answer:

x=-4

Step-by-step explanation:

(x+4) ^ (1/3) + (2x+8) ^ (1/3) = 0

Subtract (x+4) ^ (1/3) from each side

(x+4) ^ (1/3) - (x+4) ^ (1/3)+ (2x+8) ^ (1/3) = -(x+4) ^ (1/3)

(2x+8) ^ (1/3) = -(x+4) ^ (1/3)

Cube each side

(2x+8) ^ (1/3) ^3= -(x+4) ^ (1/3)^3

2x+8 = -(x+4)

Distribute the negative sign

2x+8 = -x -4

Add x to each side

2x+8 +x =-x+x-4

3x+8 = -4

Subtract 8 from each side

3x+8-8 =-4-8

3x =-12

Divide by 3

3x/3 = -12/3

x = -4

8 0
3 years ago
Read 2 more answers
Someone please help explain how to find x
dimaraw [331]

Answer:

x=27

Step-by-step explanation:

180-2x-40+180-3x+180-x-50+180-4x = 360

360-2x-40-3x+360-x-50-4x= 360

360-10x-90= 0

10x= 270

x= 27

5 0
4 years ago
Annie’s change purse contained 5 quarters 8 dimes and 8 nickels if Annie chose 2 coin randomly without replacing them in her pur
Bogdan [553]
<h3>Answer:</h3>

2/15

<h3>Explanation:</h3>

There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.

Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.

_____

<em>Comment on nCk</em>

The number of ways to choose k objects from n, when order does not matter, is ...

... n!/(k!(n -k)!)

For the computations above, we have ...

... 8C2 = 8·7/(2·1) = 28

... 21C2 = 21·20/(2·1) = 210

8 0
3 years ago
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