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ss7ja [257]
2 years ago
13

If the sum of three consecutive terms of an AP is 15 and

Mathematics
2 answers:
vaieri [72.5K]2 years ago
8 0

Answer:common difference is 2.24

Step-by-step explanation:

Temka [501]2 years ago
6 0

Step-by-step explanation:

Let the three consecutive terms in AP a - d, a, &.

a + d

\therefore \: a  - d + a + a + d = 15 \\  \therefore \:3 a  = 15 \\  \therefore \: a  =  \frac{15}{3}  \\ \therefore \: a  =  5 \\  \\ \because (a  - d ) \times  a  \times ( a + d ) = 100 \\ \therefore \: a  ( {a}^{2}  -  {d}^{2} ) = 100 \\ \therefore \: 5  ( {a}^{2}  -  {d}^{2} ) = 100\\ \therefore \:  ( {a}^{2}  -  {d}^{2} ) =  \frac{100}{5}  \\ \therefore \:  ( {5}^{2}  -  {d}^{2} ) =  20 \\ \therefore \: 25  -  {d}^{2} =  20 \\ \therefore \: 25 - 20 =  {d}^{2}  \\  \therefore \:{d}^{2} = 5 \\ \therefore \:{d} =  \pm\sqrt{5}  \\  \\ thus \: first \: term \: (a) = 5 \\ common \: difference \:  (d)=  \pm\sqrt{5}

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