Select all statements that are true about the linear equation.
1 answer:
<h2>Linear equations</h2><h3>Concept</h3>
Linear equations, or a straight line on a graph, generally consist of two variables, x, and y - as well as slope.
<h3>Utilization</h3>You have been provided a linear equation in slope-intercept form (y=mx+b). Let's look at the true and false statements now:
The graph of the equation is the set of all points that are solutions to the equation, TRUE or FALSE. The answer to this is true, because any point on the line should provide a valid solution to the problem. TRUE
The point (10, 3) is on the graph of the equation. We have already determined that in order for a point to be on the line - it must be a solution... so, plug it in and test:
3 is not equal to 118, so the point (10,3) is not on this line. FALSE
The point (−2,−1) is on the graph of the equation. Use the same setup as before:
-1 is not equal to -25, so this point is once again, not on the line. FALSE
The graph of the equation is a single point representing one solution to the equation. This is nearly the inverse of the first statement, so we can rule this out as well. FALSE
<h3>Answer</h3>The only true statement here seems to be The graph of the equation is the set of all points that are solutions to the equation. Hope this helps you!
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By running in a bearing of 127°, Paul motion is in the south eastern direction.
Correct responses:
a. Please find attached the required diagram created with MS Visio
b. Paul's distance travelled east is approximately 11.98 km
- Paul's distance travelled south is approximately 0.903 km
Given:
The distance Paul runs = 1.5 km
The bearing Paul is running = 127°
a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction
Please find attached the diagram representing the situation, created with MS Visio.
b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;
- Paul's distance east = 15 km × cos(37°) ≈ <u>11.98 km</u>
Pau's distance travelled in the south direction relative to the starting point
is given by the vertical distance travelled relative to the x-axis, which is
given as follows;
Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>
Learn more about bearings in trigonometry here:
