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3 years ago

Line a is parallel to line b, m 6=85, and m 3=2x. Find m 1.

Mathematics

2 answers:

Paladinen [302]3 years ago

3 0

Since a line =180 degrees you could set it up as (180-85) and you would get 95.
Hope this helps!!!

Sergeu [11.5K]3 years ago

3 0

Answer:

m ∠1 = 95.

Step-by-step explanation:

Given : Line a is parallel to line b, angle 6 = 85, and angle 3 =2x.

To find : Find m ∠1.

Solution : We have given that Line a is parallel to line b,

By the transversal angles property : m ∠3 and m ∠6 are the pair of interior angles on the same side of the transversal is supplementary.

m ∠3 + m ∠6 = 180

2x + 85 = 180 .

2x = 180 -85.

2x = 95

Then m ∠3 = 95.

m ∠3 and m ∠1 are vertically opposite angles are equal.

m ∠3 = m ∠1

m ∠1 = 95.

Therefore, m ∠1 = 95.

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azamat

Question 6

Given:

QR = RS

QR = x + 6

RS = 4x

To find:

Length of line segment QS

Steps:

We know QR = RS, so substituting we get,

x + 6 = 4x

6 = 4x - x

6 = 3x

6/3 = x

2 = x

x = 2

Now,

QS = QR + RS

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Therefore, the length of QS is 16 units

Question 7

Given:

QR = RS

QR = 2x - 2

RS = 2x

To find:

Length of line segment QS

Steps:

We know that QR = RS, so substituting the values we get,

QR = RS

3x - 2 = 2x

3x - 2 - 2x = 0

3x - 2x = 2

x =2

Now,

QS = QR + RS

QS = 3x - 2 + 2x

QS = 3(2) - 2 + 2(2)

QS = 6 - 2 + 2(2)

QS = 6 - 2 + 4

QS = 4 + 4

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Therefore, the length of QS is 8 units

Happy to help :)

If u need any help feel free to ask

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sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ cannot be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

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