A gardener purchases a ceramic planter, in the shape of a hemisphere, for a small batch of leftover annuals. The volume of a hemisphere is modeled by the function V = 2/3πr 3
<span>A. Write a model for the radius as a function of the volume. </span>
<span>B. The label on the planter says that it holds approximately 134 cubic inches of potting soil. What is the radius of the planter, rounded to the nearest inch? Use 3.14 for π </span>
<span>r = ∛[(3/2)V) / π] </span>
<span>134 = (2/3) (3/14) r^3 </span>
<span>r = ∛[(3/2) (134) / 3.14] ≈ 4.00 inches </span>
In this problem you would set these two equations equal to each other.
$8+ $1.50x = $10+ $1x
After this you would simplify the equation to isolate x (being the number of toppings you put on the pizzas)
$8+ 1.50x =$10+ 1x
-8 -8
----------------------------
$1.50x = $2 + $1x
-1x -1x
---------------------------
$.50x/.50 = $2/.50
_______________
x= 4 toppings and the pizzas would equal $14 total
Answer: the actual amount that Luke paid including tax is $55.65
Step-by-step explanation:
The initial price of the jacket is $75.
Luke bought a jacket that was 30% off the cost. This means that the amount of discount on the Jacket is
30/100 × 75 = 0.3 × 75 = $22.5
The price of the jacket after the discount had been applied is
75 - 22.5 = $52.5
He paid sales tax of 6% after the discount had been applied. This means that the amount of sales tax that he paid on the jacket is
6/100 × 52.5 = 0.06 × 52.5 = 3.15
Therefore, the actual amount that Luke paid including tax is
52.5 + 3.15 = $55.65
Answer:
D : This is because there are 8 outcomes and 2 events.
It cannot be C as C does not show true event outcomes on each H or T event.
Step-by-step explanation:
Answer: 4.20 gigabyte
Step-by-step explanation:
Based on the information given in the question, the equation that can be used to determine the the number of gigabytes of data Peyton can use while staying within her budget will be:
48 + 3g = 60.60
3g = 60.60 - 48
3g = 12.60
g = 12.60/3
= 4.20
The number of gigabytes of data is 4.20g
