The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
The y intercept is (0,-2)
Answer:
3600 gallons of water was removed from the basement.
Step-by-step explanation:
Given:
Rate of each pump = 40 gallons/min
We need to find find the number of gallons of water removed from the basement.
Solution:
Now Given:
After half an hour, the one pump burns out.
Now we know that;
1 hour = 60 mins
hour = 
Now for 30 mins both the pumps were working and removing the water.
So we can say that;
Water remove for first 30 mins = 
Also Given:
the second pump finishes removing the water half an hour later.
So we can say that;
Water removed for next 30 mins = 
Now we can say that;
Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .
framing in equation form we get;
Total water removed from the basement = 
Hence 3600 gallons of water was removed from the basement.
Answer:
Approximately, 6.283..
Step-by-step explanation:
First calculate the area of the whole circle
We have radius(r)=4 cm
Area of circle(a)=pir^2
=pi×(4)^2
=pi×16
=Approximately,50.265......
A cirlce has a total of 360 degrees
Therefore,we can conclude 360 degrees=50.265...
or,1 degree=50.265/360
1 degree=Approximately,0.139
Now,
Area for the shaded region = Area of 45 degree
=0.139×45=Approximately,6.283.....
Therefore,the area of the shaded region is approximately,6.283....