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timofeeve [1]
3 years ago
13

Solve the systems of equation by graphing (Picture provided)

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Answer:

The option d

Step-by-step explanation:

find the intersection with x and y

https://tex.z-dn.net/?f=x%3D0%0A

https://tex.z-dn.net/?f=0%2By%3D-9%20%5Clongrightarrow%20y%3D-9%0A

and https://tex.z-dn.net/?f=y%3D0%0A

https://tex.z-dn.net/?f=x%2B0%3D-9

we get the coordinates

https://tex.z-dn.net/?f=(0%2C-9)%2C%20(-9%2C0)

and the same process for another equation

https://tex.z-dn.net/?f=4*(0)%2By%3D-19%20%5Clongrightarrow%20y%3D-19%5C%5C%0A4*x%2B0%3D-19%20%5Clongrightarrow%20x%3D%5Cfrac%7B-19%7D%7B4%7D%20%5C%5C%5C%5C%0A(0%2C-19)%2C%20(%5Cfrac%7B-19%7D%7B4%7D%2C0)%20

and these coordinates are those expressed in the d graph

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The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.
sammy [17]
\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\
\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4
Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5

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