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mario62 [17]
2 years ago
15

On the first day in each month, Enid deposited $4 into her bank account and Jim deposited $3 into his. They opened these account

s on May 15, 1990. On December 31, 1990, they each had $72 dollars in their account. How much did each person deposit on May 15?
Mathematics
1 answer:
ohaa [14]2 years ago
5 0

Answer:

The amount of money in Enid bank account can be written as a linear equation.

Ye = Xe + $4*m

where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.

For Jim, the equation is similar:

Yj = Xj + $3*m

where Yj and Xj are similar as above.

Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).

Then we have that:

Ye = $72 = Xe + $4*7 = Xe + $28

Xe = $72 - $28 = $44

So in May 15, Enid deposited $44.

For Jim we have:

Yj = $72 = Xj + $3*7 = Xj + $21

Xj = $72 - $21 = $51

So in May 15, Jim deposited $51.

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<em>1. Sample Mean = 2.50 </em>

<em>2. Sample Variance = 1.35</em>

<em>3. Standard Deviation = 1.16</em>

Step-by-step explanation:

Note: As this question is not complete, similar can be found on internet where following are asked to calculate and here I will calculate these as well.

1. Sample Mean.

2. Sample Variance.

3. Sample Standard Deviation.

So, for sample mean to calculate from the given data points. We need to apply to following formula to calculate sample mean.

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Sample Mean = (0.17 + 1.94 + 2.62 + 2.35 + 3.05 + 3.15 + 2.53 + 4.81 + 1.92) divided by (9).

<em>Sample Mean = 2.50</em>

Likewise, from the answer of sample mean we can calculate sample variance by following steps.

<u><em>Solution: </em></u>

1.      Subtract the obtained mean from each of the data point given.

       (0.17 - 2.50) = -2.33

       (1.94 - 2.50) = -0.56

       (2.62 - 2.50) = 0.12

       (2.35 - 2.50) = -0.15

       (3.05 - 2.50) = 0.55

       (3.15 - 2.50) = 0.65

       (2.53 - 2.50) = 0.03

       (4.81 - 2.50) =  2.31

       (1.92 - 2.50) = -0.58

2.      Square each of the differences obtained in step 1.

            -2.33^{2} = 5.43

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               0.12^{2} = 0.01

            -0.15^{2} = 0.02

              0.55^{2}  = 0.30

              0.65^{2}  = 0.42

              0.03^{2} = 0.01

              2.31^{2} = 5.34    

           -0.58^{2} = 0.34    

3.  Sum all of these squares.

(5.43 + 0.31 + 0.01 + 0.02 + 0.30 + 0.42 + 0.01 + 5.34 + 0.34) = 12.18

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<em>Sample Variance =  12.18/9 = 1.35</em>

Now, by using sample variance, we can calculate standard deviation with easy simple steps.

So, in order to find standard deviation, we just need to take the square root of sample variance that we have already calculated above.

<em>Standard Deviation = </em>\sqrt{1.35}<em> = 1.16 </em>

<em>Good Luck!</em>

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