The number of three-digit positive integers that have three different digits and at least one prime digit are 7960.
The only two components in prime numbers are 1 and the number itself.
Any whole number greater than one is a prime number.
It has exactly two factors—1 and the actual number.
There is just one 2-digit even prime number.
Every pair of prime numbers is always a co-prime.
The product of prime numbers can be used to represent any number.
Three-digit positive integers that have three different digits and at least one prime digit = 3!*4!*10*9 = 7960
Learn more about prime numbers here:
brainly.com/question/145452
#SPJ1
Answer:
4,680
Step-by-step explanation:
- 45 × 104 = 4,680
I hope this helps!
Answer:ok give me two minutes
Step-by-step explanation:
Think of the inequalities as equations in the form of y=Mx+b. Notice how choices C and D match the line shown in the graph if they are seen as linear functions. Now look at the inequality. Since the shaded region is below the line, y must be less than what is input. The correct answer must be choice D.
-R
P.S. if you found this helpful, plz leave a “thanks”. Thx!
photo math duhhhhhhhhhhhhhhhhhhhh