Answer:
100.3 units²
Step-by-step explanation:
✅Find the area of the parallelogram:
Area of Parallelogram is given as base × height
base = 10
height = 5
Area of Parallelogram = 10*5 = 50
✅Next, find the area of the two semicircles:
The two semicircles = 1 circle
Area of circle = πr²
r = 8/2 = 4
Area = π*4² = 16π = 50.3 (nearest tenth)
✅Area of figure = 50 + 50.3 = 100.3 units²
Answer: x= 182 - 12x
Step-by-step explanation:
Alright, so the area of one paper is 297mm*420mm=124740mm^2. Multiplying that by 6 due to 6 sheets, we get 748440mm^2. Converting mm^2 to m^2, since we know that 1000mm=1m, we simply do (1m/1000m)^2=1m^2/1,000,000mm^2. Our equation is now
748440mm^2*1m^2/1,000,000mm^2=0.748440m^2 by crossing out the millimeters. Lastly, since it's 80g/1m^2, we multiply our number by that to get 59.8752g
Answer: (D) No. The corresponding pairs of sides must also be marked congruent to determine that the triangles are congruent.
==================================================
Explanation:
The arc markings tell us how the angles pair up, and which pairs are congruent. Eg: The double-arc angles are the same measure.
Despite knowing that all three pairs of angles are congruent, we don't have enough information to conclude the triangles are congruent overall. We can say they are similar triangles (due to the AA similarity theorem), but we can't say they are congruent or not. We would need to know if at least one pair of sides were congruent, so that we could prove the triangles congruent.
The list of congruent theorems is
- SSS
- ASA
- AAS (or SAA)
- SAS
- HL
- LL
Much of these involve an "S", to indicate "side" (more specifically "pair of sides). Both HL and LL involve sides as well. They are special theorems dealing with right triangles only.
------------
So in short, we don't have enough info. We would have to know information about the sides. This is why choice D is the answer.
Answer:
The distributive property lets you multiply a sum by multiplying each addend separately and then add the products. ... Consider the first example, the distributive property lets you "distribute" the 5 to both the 'x' and the '2'.
Step-by-step explanation: