Answer:
AC is about 41. 095 miles long.
Step-by-step explanation:
You can use the Law of Cosines to solve this: c^2 = a^2 + b^2 – 2ab cos(C)
Substitute in your values, and you're good to go!
c^2=16^2+28^2-2(16)(28)(cos(117))
c^2 = 256 + 784 - 896(cos(117))
c = sqrt(1040 - 896(cos(117)))
c is about 41. 095 miles long.
You saved 4 months
1,328.9×4
=5,315.6
half in each account
5,315.6÷2
=2,657.8
CD interest
2,657.8×0.045×(45÷365)
=14.75
Saving account
2,657.8×0.032×(45÷365)
=10.49
14.95 + 10.63 = $25.58 total interest earned
Hope it helps
Answer:
(a) the new angle the ladder makes with the ground is
(b) the ladder slipped back about 5 meters
Step-by-step explanation:
Notice that the ladder doesn't change its length in the process.
So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:
therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.
Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:
To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:
Now fro the new position of the bottom of the ladder relative to the wall:
then the difference in between those two distances is what we need:
8.4 m - 3.4 m = 5 m
X=32 because both equations are equal to 180 degrees (3x+22°+x+30°=180) just solve that equation and you’ll get your answer
Whether it can be equal to that value. For example, if 5 is greater than x, then an open circle will be useful. If 5 is greater than or equal to x, a closed circle will be used.