Question

A bag contains equal numbers of green marbles and blue marbles. You can divide all of the green marbles into groups of 12 and all the blue marbles into groups of 16. Whatis the least number of each color of marble thatcan be in the bag

Answer 1

Answer: 48

Step-by-step explanation:

We need to find the least common multiple of 12 and 16.

Finding the prime factorizations of 12 and 16,

$12=2^{2} \times 3\\\\16=2^{4}$

Thus, the least common multiple is $2^{4} \times 3=\boxed{48}$