Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
b=0.00906m
Step-by-step explanation:
Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation
where
A=area=32.5m^2
h=altitude=7172m
b=base
Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality
solving
![\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m](https://tex.z-dn.net/?f=%5Cfrac%7B2%2832.5%29%7D%7B7172%7D%20%3D0.0090%5Btex%5D%5Cfrac%7BA%282%29%7D%7Bh%7D%20%3Db%5C%5Cb%3D0.00906m)
You can simplify this expression with PEMDAS (parentheses, exponents, multiplication/division, addition/subtraction)
Start with the expressions in the parentheses:
4-7=-3
4+7=11
The expression now reads -2(-3)+5(11). Now, simplify the multiplication expressions:
-2*-3=6
5*11=55
The expression is 6+55 which is 61.
Hope this helps!!
I think it's 26.70 if I remember what a decimal is.
Answer:
Step-by-step explanation:
x2 - 4x - 12 = 0
x2 - 6x + 2x - 12= 0
x(x - 6) + 2(x - 6) = 0
x + 2 = 0
x = - 2
x - 6 = 0
x = 6
