Answer:
850 Calories.
Explanation:
The following data were obtained from the question:
Mass (M) = 50 g
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Specific heat capacity (C) of water = 1 cal/g°C
Heat absorbed (Q) =..?
Next, we shall determine the change in temperature of water.
This can be obtained as follow:
Initial temperature (T1) = 20 °C
Final temperature (T2) = 37 °C
Change in temperature (ΔT) =..?
Change in temperature (ΔT) = T2 – T1
Change in temperature (ΔT) = 37 – 20
Change in temperature (ΔT) = 17 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 50 g
Specific heat capacity (C) of water = 1 cal/g°C.
Change in temperature (ΔT) = 17 °C
Heat absorbed (Q) =..?
Q = MCΔT
Q = 50 x 1 x 17
Q = 850 Calories
Therefore, the heat absorbed is 850 Calories.
Answer:
A
Explanation:
Ohm's law is stated as E = current * resistance (E = I * R)
When you rearrange the formula, you get R = E/I
The answer is current -- A
I believe the percent yield is 56% if going by the formula of mass of actual yield/theoretical yield x 100%/
Answer:
refer attachment
Explanation:
The diagrams has been made in the attachment section. Please refer.
