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3 years ago

An anode is an electrode immersed in the half-cell where _____ takes place.

Chemistry

2 answers:

siniylev [52]3 years ago

8 0

<span>The electrodes where oxidation occurs during a cell's oxidation-reduction reaction. </span>

MrMuchimi3 years ago

5 0

If I'm not mistaken, the answer should be B. Oxidation

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The valency of calcium is2 ? what does it mean

nalin [4]

Answer:

hope you like it

Explanation:

because ouytermost shell contains two electrons

calcium is in group 2 so its valency is two valency is the number of outer shelll electrons it needs to have an stable outer shell . it needs 2 more .

5 0

3 years ago

One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silv

Flauer [41]

Answer:

1.1 × 10⁻⁴ M

Explanation:

Let's consider the following double displacement reaction.

CuCl₂(aq) + 2 AgNO₃(aq) → 2 AgCl(s)+ Cu(NO₃)₂(aq)

We can establish the following relations:

The molar mass of AgCl is 143.32 g/mol.
The molar ratio of AgCl to CuCl₂ is 2:1

The moles of CuCl₂ that reacted to produce 7.7 mg of AgCl are:

$7.7 \times 10^{-3} gAgCl.\frac{1molAgCl}{143.32gAgCl} .\frac{1molCuCl_{2}}{2molAgCl} =2.7 \times 10^{-5}molCuCl_{2}$

The molarity of CuCl₂ is:

$M=\frac{2.7 \times 10^{-5}molCuCl_{2}}{0.250L} =1.1\times 10^{-4} M$

7 0

3 years ago

In the formula 5CaSO4 the total number of sulfur atoms present is a. 1. b. 5. c. 9. d. 20?

podryga [215]

The answer is b . (1*5=5)

4 0

3 years ago

Read 2 more answers

Calculate the molecular (formula) mass of each compound: (a) iron(ll) acetate tetrahydrate; (b) sulfur tetrachloride; (c) potass

Nutka1998 [239]

Answer:

a) Iron(ll) acetate tetrahydrate: 245,68 g/mol

b) Sulfur tetrachloride: 173,87 g/mol

c) Potassium ermanganate 158,034 g/mol

Explanation:

To solve this kind of exercises you must look for the number of atoms in each molecule first, then look on the periodic table the atom weight and the multiply the atom weight times the quantity of each atom. For instance:

The molecule of Iron(II) acetate itetrahydrate is (CH3COO)2Fe•4H2O, it means that you have:

2 atoms of carbon times the atomic weight of C (12.00g/mol)= 24g

14 atoms of Hidrogen times the atomic weight of H (1,00g/mol)= 14g

6 atoms of Oxigen times the atomic weight of O (16,0g/mol)= 96

2 atoms of Iron times the atomic weight of Fe (55,84g/mol)= 111,68g

At last, you only have to add the results: 24+14+96+11,68= 245,68g/mol. This example was for the first molecule.

See you,

5 0

3 years ago

Please help Asap………………

vladimir2022 [97]

Answer:

3rd

Explanation:

6 0

3 years ago

Read 2 more answers