Question

PLEASE HELP!!!! WILL GIVE 99 PTS! :)Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 54 km/h. After four hours, the velocity of the car is 58 km/h.
Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)

Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)

Answer 1

t = time

v = velocity

you have (2,54) & (4,58)

v-54 = (58-54) / (4-2) *(t-2)

v=4/2(t-2)+54

v =2(t-2)+54

v = 2t-4+54

b - Graph by plotting the given points (2,54) & 4,58) and drawing a straight line through them

Answer 2

Since we have two points (2,54) and (4,54), we can assume a linear function and solve for the slope and intercept. So if V=kt+b where t is time passed and v is velocity of the car, we can plug in and solve for k and t, that would give t as a function of v, and you can graph it