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svetlana [45]
3 years ago
12

Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn II contains 6 green bal

ls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?. . A. 2/51. B. 3/20. C.1/10. D.4/153
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0
Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.

Probability of blue balls:
Urn 1 : P = 6/10 
Urn 2 : P = 2/8 

Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20 

Answer is B. 3/20
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Julie needed to serve 9 ounces of potato salad to each guest at a picnic. She has 9 guests. How many ounces of potato would she
Goryan [66]
She has to give 9 ounces of potato salad to each guest and 9 guests coming over.
EQUATION: 9*9=amount of potato salad=81 ounces
3 0
3 years ago
Given: △DMN, DM=10 3 m∠M=75°, m∠N=45° Find: Perimeter of △DMN
OlgaM077 [116]

Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...

... 30-60-90: 1 : √3 : 2

... 45-45-90: 1 : 1 : √2

The long side of ΔMDX is 10√3, so the other two sides are

... MX = MD(√3/2) = 15

... DX = MD(1/2) = 5√3

The short side of ΔMNX is MX = 15, so the other two sides are

... NX = MX(1) = 15

... MN = MX(√2) = 15√2

Then the perimeter of ΔDMN is ...

... P = DM + MN + NX + XD

... P = 10√3 +15√2 + 15 + 5√3

... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN

5 0
3 years ago
6 fl oz= how many cups
natima [27]
1 oz = 0.125 cups so 6 oz = 0.75 cups

Hope this helps!
3 0
3 years ago
Read 2 more answers
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
4 years ago
If four times the sum of a number and 3 is divided by 2, the quotient is 0: find the number
AveGali [126]

The other number is -3.

Step-by-step explanation:

Step 1; First we develop formulae for the given information. A number is added with 3 and the resulting sum is multiplied by 4. This number is then divided by 2 and the quotient is 0. Assume the unknown number is x, then the given information is as follows

The quotient of \frac{4(x+3)}{2} is 0. So \frac{4(x+3)}{2} = 0.

Step 2; Now we solve the above equation. The denominator is taken to the RHS and the RHS remains zero.

\frac{4(x+3)}{2} = 0, 4(x+3)= 0, 4x+ 12 = 0, 4x = -12, x = \frac{-12}{4} = -3.

So the other number is -3.

3 0
4 years ago
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