Question

What is the Vertex y=2x^2+6

Answer 1

Compare this function to y=ax^2 + bx + c.  You can readily see that a=2, b=0 and c=6.

The x-coord. of the vertex is at x = -b / (2a).  Subbing the given values for a and b, we get 

x = -(0) / (2(2) = 0.  At x = 0, y = 6, so the vertex of this parabola is (0,6).  It opens upward.