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2 years ago

11

What is the Vertex y=2x^2+6

1 answer:

inessss [21]2 years ago

4 0

Compare this function to y=ax^2 + bx + c. You can readily see that a=2, b=0 and c=6.

The x-coord. of the vertex is at x = -b / (2a). Subbing the given values for a and b, we get

x = -(0) / (2(2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.

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3144 divided by 9 and how you got it :) for brainliest

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3144/9= 349.33

I used a calculator, but you can also solve this by long division (if a calculator isn’t available)

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IgorC [24]

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2 years ago

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Art [367]

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2 years ago

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4. Which of the following lines is perpendicular to y = -2X + 8?

Alenkinab [10]

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

That is to say:

$m_ {1} * m_ {2} = - 1$

We have the following equation:

$y = -2x + 8$

So:

$m_ {1} = - 2$

Thus:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- 2}\\m = \frac {1}{2}$

Thus, a line perpendicular to the given line must have slope $m = \frac {1} {2}.$

Option A:

$x + 2y = 8\\2y = -x + 8\\y = - \frac {1} {2} x + 4$

It is not perpendicular!

Option B:

$x-2y = 6\\2y = x-6\\y = \frac {1} {2} x-3$

If it is perpendicular!

Option C:

$2x + y = 4\\y = -2x + 4$

It is not perpendicular!

Option D:

$2x-y = 1\\y = 2x-1$

It is not perpendicular!

The correct option is option B

ANswer:

Option B

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2 years ago