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Lostsunrise [7]
3 years ago
5

If 2 : 9 = x : 18, then find the value of x

Mathematics
2 answers:
Anni [7]3 years ago
3 0

Answer:

4

Step-by-step explanation:

4 is the answer

Bad White [126]3 years ago
3 0

Answer:

4

Step-by-step explanation:

2/9=x/18

9x=36

<u>x=4</u>

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Write the fractional equivalent (in reduced form) of each number.
ladessa [460]

Answer:

1) 1/10

2)16/100

3)6..../10

4) 3/5

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Step-by-step explanation:

8 0
3 years ago
Expand and simplify <br><br> A. (x – 2y)(y – 3x)<br><br> B. (2p+3)(p^2-4p-7)
emmasim [6.3K]

Answer:

A. (x−2y)(y−3x)

=(x+−2y)(y+−3x)

=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)

=xy−3x2−2y2+6xy

=−3x2+7xy−2y2

B. (2p+3)(p2−4p−7)

=(2p+3)(p2+−4p+−7)

=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)

=2p3−8p2−14p+3p2−12p−21

=2p3−5p2−26p−21

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5 0
2 years ago
4, 5, 6 is it a right triangle, acute, or obtuse
maxonik [38]

Answer:

it is an acute scalene triangle

3 0
3 years ago
Read 2 more answers
Six times a number is decreased by 20 which is equal to three times the number increased by 4. what is the number?​
loris [4]
Let the number be a
6a - 20 = 3a + 4
Group like terms
6a - 3a = 20 + 4
3a = 24
divide through by 3
a = 8
Therefore the number is 8
8 0
2 years ago
HELP ASAP PLEASE I NEED ANS N SOLUTION
Blababa [14]

Given:

A bowl contains 25 chips numbered 1 to 25.

A chip is drawn randomly from the bowl.

To find:

The probability that it is

a. 9 or 10?

b. even or divisible by 3?

c. divisible by 5 and divisible by 10?

Solution:

a. We have,

Number of total chips = 25

Favorable out comes are either 9 or 10. So,

Number of favorable outcomes = 2

The probability that the selected chip is either 9 or 10 is:

\text{Probability}=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}

\text{Probability}=\dfrac{2}{25}

Therefore, the probability that the selected chip is either 9 or 10 is \dfrac{2}{25}.

b. The numbers that are even from 1 to 25 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24.

The numbers from 1 to 25 that are divisible by 3 are 3, 6, 9, 12, 15, 18, 21, 24.

The numbers that are either even or divisible by 3 are 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24.

Number of favorable outcomes = 16

The probability that the selected chip is either even or divisible by 3 is:

\text{Probability}=\dfrac{16}{25}

Therefore, the probability that the selected chip is either even or divisible by 3 is \dfrac{16}{25}.

c. The numbers from 1 to 25 that are divisible by 5 are 5, 10, 15, 20, 25.

The numbers from 1 to 25 that are divisible by 10 are 10, 20.

The numbers that are divisible by both 5 and 10 are 10 and 20.

Number of favorable outcomes = 2

The probability that the selected chip is divisible by 5 and divisible by 10 is:

\text{Probability}=\dfrac{2}{25}

Therefore, the probability that the selected chip is divisible by 5 and divisible by 10 is \dfrac{2}{25}.

5 0
2 years ago
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