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Mekhanik [1.2K]
3 years ago
13

Addition and Multiplication are inverse operations. True or False?

Mathematics
1 answer:
sdas [7]3 years ago
6 0
Its False. addition and subtraction, Multiplication and division are inverse operations.
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1/5n+3/5n=7/9<br><br> Can you help?
ArbitrLikvidat [17]

The value of n in 1/5n+3/5n=7/9 is 35/36

<h3>How to solve the equation?</h3>

The equation is given as:

1/5n+3/5n=7/9

Multiply through by 5

n + 3n = 35/9

Evaluate the sum

4n = 35/9

Divide both sides by 4

n = 35/36

Hence, the value of n in 1/5n+3/5n=7/9 is 35/36

Read more about equations at:

brainly.com/question/723406

#SPJ1

4 0
2 years ago
The chicken pen held 7 chickens. Each chicken lay 6 eggs a day. How many eggs world they get altogether after 30 days.
Tcecarenko [31]

Answer:

1260 eggs in 30 days

7*6=42

42*30=1260

3 0
2 years ago
Read 2 more answers
HELP<br> 35) Find the measure of line segment WV.<br> A) 3<br> B) 4<br> C) 5<br> D) 6
frozen [14]

Step-by-step explanation:

secants originating from the same point have the same relative length relationship :

outside part × sum of outside and inside parts

is the same for every secant from the same point.

so,

5×(7+5) = 6×(2x-8+6) = 12x - 12

60 = 12x - 12

12x = 72

x = 6

WV = 2x - 8 = 2×6 - 8 = 12 - 8 = 4

so, B is correct.

8 0
2 years ago
Can someone literally cash app me a dollar at $AlphaDawggg it will really make my day
ozzi

Answer:

no lolololololololololol

5 0
3 years ago
Solve for x: 1 1/5 x -2 1/3 &lt; 1/7 x+ 1 1/2
Firlakuza [10]
Solving inequalities is similar to solving a regular equation. The only thing you need to worry about with inequalities is that when you are dividing or multiplying by a negative number, you must flip the inequality sign. You won't have to worry about that here if the coefficient in front of x is positive when you divide!

Also remember:
- To add/subtract fractions, you have to turn all mixed numbers into improper fractions (if needed), <span>find a common denominator on both fractions (if needed), add/subtract the numerators, put the sum/difference over the common denominator, and simplify if needed. 

- To multiply fractions, multiply the numerators and multiply the denominators. Put the product of the numerators over the product of the denominators.

- To divide fractions, remember that dividing by a fraction is the same as multiplying by the inverse of that fraction (aka fraction flipped). 

- To turn mixed numbers into improper fractions, multiply the whole number by the denominator of the fraction. Add the numerator of the fraction to the product you get, and put that final sum over the original denominator.

Back to the problem:
</span>You are told that 1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2} and you have to solve for x.
<span>
1) </span>Using the info for converting mixed numbers to improper fractions from above, you know that 1 \frac{1}{2} =  \frac{3}{2} and 2 \frac{1}{3} =  \frac{7}{3} and 1 \frac{1}{5} x =  \frac{6}{5} x. Now add/subtract using the info above, isolating the variable x by adding 2 \frac{1}{3} to both sides and subtracting \frac{1}{7} x from both sides. 
1 \frac{1}{5} x - 2 \frac{1}{3} \ \textless \ \frac{1}{7} x + 1 \frac{1}{2}\\&#10;\frac{6}{5} x -  \frac{7}{3} \ \textless \ \frac{1}{7} x + \frac{3}{2}\\&#10;(\frac{6}{5} x  - \frac{1}{7} x) \ \textless \ (\frac{3}{2} + \frac{7}{3})\\&#10;(\frac{42}{35} x  - \frac{5}{35} x) \ \textless \ (\frac{9}{6} + \frac{14}{6})\\&#10; \frac{37}{35} x \ \textless \   \frac{23}{6}

2) Divide both sides by \frac{37}{35} to get the inequality for x. Remember the info for dividing from above:
\frac{37}{35} x \ \textless \ \frac{23}{6}\\&#10;x \ \textless \  \frac{23}{6} \div \frac{37}{35}  \\&#10;x \ \textless \  \frac{23}{6} \times \frac{35}{37} \\&#10;x \ \textless \  \frac{805}{222}

Your final answer is x < \frac{805}{222} or x < 3 \frac{139}{222}.
3 0
3 years ago
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