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Natasha_Volkova [10]
4 years ago
12

Maths - how dou do it and answer pls show working

Mathematics
1 answer:
Marina CMI [18]4 years ago
4 0
Fractions that are n/99 will repeat every 2 digits. 
The 2 digits they repeat are the digits in the numerator, which should be 18
Therefore the fraction is 18/99 = 2/11.
There's no real way to work the problem except for guess and check or knowing these facts.
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The following equation is true for all real values of k for which the expression on the left is defined, and A
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Answer:

A = 6k(k + 6)

Step-by-step explanation:

We have to solve the given equation for the value of A,

\frac{6k^2-36k}{A}.\frac{k^2+12k+36}{k^2-36}=1

\frac{(6k^2-36k)(k^2+12k+36)}{A(k^2-36)}=1

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A = 6k(k + 6)

Therefore, value of A is 6k(k + 6).

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