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Korvikt [17]
3 years ago
6

16 VO What is the volume of a box that will hold exactly 567 of these cubes 1/3

Mathematics
2 answers:
g100num [7]3 years ago
5 0
Pointsssssssss thank you :)

Step by step;
Nana76 [90]3 years ago
3 0
21 cubic inches is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides.
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I’m struggling with problems 4 thru 7 and thought someone could help me
antiseptic1488 [7]

Answer:

42+t

q×10 or Q(10)

x+4

1/2y

Step-by-step explanation:

there are 42 members and their combined total would be the answer

Q is the number of members now, 10 is what you need to times it by in order to get the original number of members

the sister is 4 years younger than her brother, therfor he must be 4+ older than her

half of Y would be 1/2Y

6 0
3 years ago
How to convert improper fractions to a mixed numeral
Deffense [45]
Say for example, you have the improper fraction 18/7
The first step is to find out how many times 7 fits into 18
This looks like flipping the fraction, 7/18 = 2 whole times  with 4 parts left over
The 4 left over gets put in front of the original number (7) to give 2 4/7

To check if you have done it correctly, multiply the whole number (2) by the denominator ( 7 ) and then add the numerator.
2 x 7 = 14 + 4 = 18

Hope this helps
4 0
3 years ago
Read 2 more answers
HELP BRAINISET TO WHOEVER RIGHT
Natasha_Volkova [10]

Answer:

A: 171.75

B: 170

Step-by-step explanation:

The mean (or average) can be found by...

- add all the numbers together (we will call this y)

- divide the total sum (or y) by the total amount of numbers used to add

Formula:

(x₁ + x₂ + x₃ + ... + xₙ) ÷ n

For A:

(172 + 130 + 173 + 212) ÷ 4 = 171.75

For B:

(136 + 184 + 168 + 192) ÷ 4 = 170

8 0
3 years ago
All the edges of a regular square pyramid have length 8 . What is the:
user100 [1]

Answer:

vol=BX1/3 h

=64* 1/3 square root of 32

Step-by-step explanation:

5 0
3 years ago
If f(x) = 4x² – 3x + 8, then f(-2) =
Citrus2011 [14]

Answer: 30

Step-by-step explanation:

16+6+18

7 0
3 years ago
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