All categories

3 years ago

16 VO What is the volume of a box that will hold exactly 567 of these cubes 1/3

Mathematics

2 answers:

g100num [7]3 years ago

5 0

Pointsssssssss thank you :)

Step by step;

Nana76 [90]3 years ago

3 0

21 cubic inches is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides.

You might be interested in

A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the

hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone = 2 m

The angle which the A $\hat O$ C = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone

The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°

∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0

3 years ago

This wind would be called a

Rina8888 [55]

Southeast, because it is between south and east on a compass

7 0

2 years ago

Read 2 more answers

Help, please the question and thank you

Fynjy0 [20]

Answer:

Step-by-step explanation:

If A = (2, 3) then a dilation of scale factor 2 means that the x and y coordinates are multiplied by 2, so x = 2 x 2 = 4 and y = 3 x 2 = 6, so A' = (4, 6)

8 0

2 years ago

1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.

PIT_PIT [208]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6$

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10$

8 0

4 years ago

What is the measure of an angle whose sine is√3/2 ? 60 45 30

dem82 [27]

ANSWER

The required angle is
$60 \degree$

EXPLANATION

Let the angle whose sine is
$\frac{ \sqrt{3} }{2}$
be
$x \degree$

Then

$\sin(x \degree) = \frac{ \sqrt{3} }{2}$

We take the inverse sign of both sides to obtain,

$x = \sin ^{ - 1} ( \frac{ \sqrt{3} }{2} )$

We use our scientific calculator to evaluate and obtain,

$x = 60 \degree$

8 0

3 years ago

Read 2 more answers